Solution du 7ème exercice du 3ème degré

A/ 432.000 = (480.000 x 15 /100) x n = 72000 x n
n = 432.000/72000 = 6 ans
la date d’acquisition : le 01/0/087

B/ 94250 = (75000 x Tx /100 ) x 3 + (75000 x Tx /100 )x 8/12 + (51000 x Tx /100 )x2
= 2250 Tx + 500 Tx + 1020 Tx
= 3770 Tx
Tx = 94250/3770 = 25%

C/ Matériel outillage dotation 93
Dot 93 = (480.000 x15 /100) x 8/12 = 48000
Matériel de transport dotation 93
Dot 93 = ( 75000 x 25/100) x4/12 + (51000 x 25/100)
= 6250 + 12750
= 19000