Solution du 11ème exercice du 3ème degré

A/ 161250 = (6000 x Tx /100) x 6,25 + (120000 x Tx /100) x 4

+ ( 80.000 x Tx /100) x 2,75
= 3750 x Tx + 4800 x Tx + 2200 x Tx = 10750 Tx
Tx = 161250/10750 = 15%
B/ 322000 = ( 460.000 x 20/100) x n = 92000 x n
n = 322.000 /92.000 = 3,5 ans cad 3ans et 6 mois
le matériel de transport est acquis le 01/07/85

c/ AC = ( VO x Tx/100) x n AC = VO – VNA
VNA = VO - ( VO x Tx/100) x n
15000 = VO – ( VO x10/100) x 7
VO = 15000/0,3 = 50.000
AC = VO- VNA = 50.000 – 15000 = 35000

D/ Dotation du matériel outillage

Dot 89 = ( 60000 x 15/100) x 5/12 + (120.000 x 15/100) + ( 80.000 x 15/100)+ (150.000x 15/100) x6/12
= 3750 + 18000 + 12000 + 11250 = 45000
dotation du matériel du transport
dot 89 = ( 460.000 x 20/100) = 92000
dotation du matériel du bureau
dot 89 = ( 50000 x 10/100) = 5000